The standard enthalpy of formation of H 2 ​ O(l) and Fe 2 ​ O 3 ​ (s) are respectively −286 kJ mol −1 and −824 kJ mol −1 . What is the standard enthalpy change for the following reaction?
Fe 2 ​ O 3 ​ (s)+3H 2 ​ (g)⟶3H 2 ​ O(l)+2Fe(s)

Explanation

To find the standard enthalpy change for the reaction:

\[ \text{Fe}_2\text{O}_3(s) + 3\text{H}_2(g) \rightarrow 3\text{H}_2\text{O}(l) + 2\text{Fe}(s) \]

we will use the standard enthalpy of formation values provided for the reactants and products.

### Step 1: Write down the standard enthalpy of formation values.
- Standard enthalpy of formation of \( \text{H}_2\text{O}(l) = -286 \, \text{kJ/mol} \)
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