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Gobar gas obtained by bacterial fermenta...

Gobar gas obtained by bacterial fermentation of animal refuse contains mainly methane. The heat of combustion of methane to `CO_2` and water (gas) is given by
`CH_4(g) + 2O_2(g) to CO_2(g) + 2H_2O (g) + 809 kJ`.
How much gobar gas would have to be produced per day for a small village community of 100 families, if we assume that each family has to be supplied 20,000 kJ of energy per day to meet all its needs and that the methane content in gobar gas is 80% by weight?

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To solve the problem, we need to determine how much gobar gas is required to meet the energy needs of a village community of 100 families, given that each family requires 20,000 kJ of energy per day and that the methane content in gobar gas is 80% by weight. ### Step-by-Step Solution: 1. **Calculate Total Energy Requirement:** Each family requires 20,000 kJ of energy per day. For 100 families: \[ \text{Total Energy} = 100 \times 20,000 \text{ kJ} = 2,000,000 \text{ kJ} = 2 \times 10^6 \text{ kJ} ...
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In a gobar gas plant, gobar gas is formed by bacterial fermentation of animal refuse. It mainly contains methane and its heat of combustion is -809kJ mol^(-1) according to following equation: CH_(4) +2O_(2) rarr CO_(2)+2H_(2)O , DeltaH =- 809 kJ How much gobar gas would have to be produced per day for a small village of 50 families, it it is assumed that each family requires 20000 kJ of energy per day? The methane content in gobar gas is 80% by mass.

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