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The reaction of cyanamide, NH(2)CN (s), ...

The reaction of cyanamide, `NH_(2)CN (s)`, with dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `-742.7 kJ mol^(-1)` at 298 K. Calculate enthalpy change for the reaction at 298 K.
`NH_(2)CH(g)+(3)/(2)O_(2)(g)rarrN_(2)(g)+CO_(2)(g)+H_(2)O(1)`

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For the given reaction,
`Deltan = (1 + 1) - (3/2) = +(1/2)` mole.
`DeltaH = DeltaU + DeltanRT`
we have, `DeltaH =- 742.7 + (1/2 xx8.314 xx 10^(-3) xx 298)`
`( :. R = 8.314 xx 10^(-3) kJ mol^(-1) K^(-1))`
`=-741.5 kJ mol^(-1)`
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