Which one of the following represents an ovule where the embryo sac becomes horseshoe-shaped and the funiculus and micropyle are close to each other?

Options

A. Amphitropous
B. Circinotropous
C. Atropous
D. Anatropous

Explanation

To solve the question regarding which type of ovule has a horseshoe-shaped embryo sac with the funiculus and micropyle close to each other, we can follow these steps:

### Step 1: Understand the Types of Ovules
There are several types of ovules, and each has distinct characteristics regarding the arrangement of the funiculus (the stalk connecting the ovule to the ovary) and the micropyle (the opening through which the pollen tube enters).

### Step 2: Identify the Characteristics of Each Type
1. **Orthotropous Ovule**: In this type, the funiculus and micropyle are located at opposite ends of the ovule. This does not fit the criteria of the question.
2. **Anatropous Ovule**: Here, the funiculus and micropyle are closer together, but the embryo sac is straight, not horseshoe-shaped. Thus, this option is also incorrect.
3. **Amphitropous Ovule**: This type exhibits a 90-degree bend, causing the embryo sac to take on a horseshoe shape, and the funiculus and micropyle are close to each other. This matches the description in the question.
4. **Circinotropous Ovule**: This type is characterized by a spirally coiled funiculus, which does not meet the criteria of the question.

### Step 3: Determine the Correct Answer
Based on the characteristics outlined:
- The **Amphitropous Ovule** is the one that has a horseshoe-shaped embryo sac with the funiculus and micropyle close to each other. Therefore, this is the correct answer.

### Final Answer:
The correct answer is **Amphitropous Ovule**.

---