Home
Class 12
MATHS
Find the value of lamda so that the stra...

Find the value of `lamda` so that the straight lines: `(1-x)/(3)= (7y -14)/(2 lamda)= (z-3)/(2) and (7-7x)/(3 lamda)= (y-5)/(1)= (6-z)/(5)` are at right angles.

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \lambda \) such that the given straight lines are at right angles, we will follow these steps: ### Step 1: Write the equations of the lines in standard form The given equations are: \[ \frac{1-x}{3} = \frac{7y - 14}{2\lambda} = \frac{z - 3}{2} \] and \[ \frac{7 - 7x}{3\lambda} = \frac{y - 5}{1} = \frac{6 - z}{5} \] We can rewrite these equations in the parametric form. For the first line, let \( t \) be the parameter: \[ x = 1 - 3t, \quad y = 2 + \lambda t, \quad z = 3 + 2t \] For the second line, let \( s \) be the parameter: \[ x = 1 - \frac{3\lambda s}{7}, \quad y = 5 + s, \quad z = 6 - 5s \] ### Step 2: Find the direction ratios of the lines The direction ratios of the first line are: \[ (-3, 2\lambda, 2) \] The direction ratios of the second line are: \[ \left(-\frac{3\lambda}{7}, 1, -5\right) \] ### Step 3: Set up the dot product condition for perpendicularity For the lines to be at right angles, the dot product of their direction ratios must equal zero: \[ (-3) \left(-\frac{3\lambda}{7}\right) + (2\lambda)(1) + (2)(-5) = 0 \] ### Step 4: Simplify the equation Calculating the dot product: \[ \frac{9\lambda}{7} + 2\lambda - 10 = 0 \] Combine the terms: \[ \frac{9\lambda + 14\lambda}{7} - 10 = 0 \] This simplifies to: \[ \frac{23\lambda}{7} - 10 = 0 \] ### Step 5: Solve for \( \lambda \) Rearranging gives: \[ \frac{23\lambda}{7} = 10 \] Multiplying both sides by 7: \[ 23\lambda = 70 \] Dividing by 23: \[ \lambda = \frac{70}{23} \] ### Final Answer The value of \( \lambda \) for which the two lines are at right angles is: \[ \lambda = \frac{70}{23} \]
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER-5

    ICSE|Exercise Section -C|10 Videos
  • MODEL TEST PAPER-5

    ICSE|Exercise Section -C|10 Videos
  • MODEL TEST PAPER-16

    ICSE|Exercise SECTION -C (65 MARKS)|10 Videos
  • MODEL TEST PAPER-6

    ICSE|Exercise Section -C|10 Videos

Similar Questions

Explore conceptually related problems

Find the value of lamda so that the lines (1-x)/(3)=(7y-14)/(2lamda)=(z-3)/(2) and (7-7x)/(3lamda)=(y-5)/(1)=(6-z)/(5) are at right angles.

Find the value of p so that the lines (1-x)/(3)= (7y-14)/(2p)= (z-3)/(2) and (7-7x)/(3p)= (y-5)/(1)= (6-z)/(5) are at right angles

Find the values of p so that the lines (1-x)/3=(7y-14)/(2p)=(z-3)/2 and (7-7x)/(3p)=(y-5)/1=(6-z)/5 are at right angles.

Find the values of lambda if the following of lines perpendicular : (1-x)/(3) = (7y-14)/(3lambda)=(z+1)/(2) and (7-7x)/(3lambda) = y/1 = (1-z)/(5)

Find the values p so that line (1-x)/3=(7y-14)/(2p)=(z-3)/2a n d(7-7x)/(3p)=(y-5)/1=(6-z)/5 are at right angles.

Find the values p so that line (1-x)/3=(7y-14)/(2p)=(z-3)/2a n d(7-7x)/(3p)=(y-5)/1=(6-z)/5 are at right angles.

Find the value of k so that the lines (1-x)/(3) = (y-2)/(2k) = (z-3)/(2) and (1+x)/(3k) = (y-1)/(1) = (6-z)/(7) are perpendicular to each other.

If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)/(-2) and (x-1)/(3k)=(y-5)/1=(z-6)/(-5) are at right angle, then find the value of k .

If the lines (x-2)/(1)=(y-3)/(1)=(z-4)/(lamda) and (x-1)/(lamda)=(y-4)/(2)=(z-5)/(1) intersect then

If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)/(2)a n d(x-1)/(3k)=(y-5)/1=(z-6)/(-5) are at right angel, then find the value of kdot