Home
Class 11
MATHS
The coefficient of x in the equation x^2...

The coefficient of x in the equation `x^2+px+q=0` was wrongly written as 17 in place of 13 and the roots thus found were -2 and -15. The roots of the correct equation are
(A) `15.-2` (B) `-3,-10` (C) `-13,30` (D) `4,13`

A

`-3 and -15`

B

`-2 and -10`

C

`-3 and -10`

D

3 and 10

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST PAPER-2021

    ICSE|Exercise SECTION - B|10 Videos

  • MOCK TEST PAPER-2021

    ICSE|Exercise SECTION - C|10 Videos

  • MEASURES OF DISPERSION

    ICSE|Exercise CHAPTER TEST|6 Videos

  • MODEL TEST PAPER - 18

    ICSE|Exercise SECTION - C|9 Videos

Similar Questions

Explore conceptually related problems

The coefficient of x in a quadratic equation x^2 + px +q=0 was taken as 17 in place of 13 and its roots found to be -3 and -10 . The roots of the original equation are

The coefficient of x in the quadratic equation x^2 + px + q = 0 was taken as 17 in place of 13. its roots were found to be - 2 and - 15. Find the roots of the original equation.

The roots of the equation x^(2)-4x+13=0 are

In copying a quadratic equation of the form x^2 + px + q = 0 , the coefficient of x was wrongly written as -10 in place of -11 and the roots were found to be 4 and 6 . find the roots of the correct equation.

The roots of the equation x^(2) - 8x + 15 = 0 are

Find the roots of the equations. Q. 2x^(2)+x-3=0

In finding the roots of x^(2) + px + q = 0 the coefficient of x was taken as -7 instead of -8 and the roots were 4 and 3 then the correct roots are

The repeated root of the equation 4x^3 -12x^2 -15x -4=0 is

The roots of the equation x^(2)-2ax+8a-15=0 are equal, then a =

If one root of the equation x^2+px+q=0 is the square of the other then