Find the square of the length of tangent from (3,4) to the curve `x^2+y^2+8x+5y-1=0`.

The square of the length of tangent from (3, –4) on the circle x^(2) + y^(2) – 4x – 6y + 3 = 0

The square of the length of tangent from (2,- 3) on the circle x^(2)+y^(2)-2x-4y-4=0 is :

Length of tangent from (8,6) to the circle x^(2)+y^(2)-3x-4y+2=0

If L_1 and L_2, are the length of the tangent from (0, 5) to the circles x^2 + y^2 + 2x-4=0 and x^2 + y^2-y + 1 = 0 then

The length of the tangent from (1,1) to the circle 2x^(2)+2y^(2)+5x+3y+1=0 is