State, with reason which of the are surds and which are not :
`sqrt(pi)`

Answer

To determine whether \( \sqrt{\pi} \) is a surd or not, we can follow these steps:

### Step 1: Understand the definition of a surd
A surd is an expression containing a root (such as a square root) that cannot be simplified to remove the root. This typically occurs when the number under the root is irrational.

### Step 2: Identify the nature of \( \pi \)
The number \( \pi \) is known to be an irrational number. This means that it cannot be expressed as a fraction of two integers, and its decimal representation is non-terminating and non-repeating.

### Step 3: Analyze \( \sqrt{\pi} \)
Since \( \pi \) is irrational, when we take the square root of \( \pi \), we are left with \( \sqrt{\pi} \). There is no way to simplify \( \sqrt{\pi} \) into a rational number because \( \pi \) itself does not have a rational square root.

### Step 4: Conclusion
Since \( \sqrt{\pi} \) contains an irrational number under the radical sign and cannot be simplified to remove the radical, we conclude that \( \sqrt{\pi} \) is indeed a surd.

### Final Answer:
**\( \sqrt{\pi} \) is a surd because it contains an irrational number under the radical sign, which cannot be simplified.**

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