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A man borrowed a sum of money and agrees...

A man borrowed a sum of money and agrees to pay it off by paying Rs 43,200 at the end of the first year and Rs 34,992 at the end of the secon years. If the rae of compound interesct is 8% per annum, find the sum borrowed.

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To find the sum borrowed by the man, we can use the concept of compound interest and the formula for the amount after a certain period. Here’s the step-by-step solution: ### Step 1: Understand the Payments The man makes two payments: - Rs 43,200 at the end of the first year - Rs 34,992 at the end of the second year ### Step 2: Total Amount Paid Calculate the total amount paid over the two years: \[ \text{Total Amount Paid} = 43200 + 34992 = 78292 \] ### Step 3: Identify the Rate and Time The rate of compound interest is given as 8% per annum, and the total time period for the payments is 2 years. ### Step 4: Use the Compound Interest Formula The formula for the amount \( A \) after \( n \) years at a compound interest rate \( r \) is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Where: - \( A \) = Total amount after \( n \) years - \( P \) = Principal amount (sum borrowed) - \( r \) = Rate of interest - \( n \) = Number of years ### Step 5: Set Up the Equation For the first payment of Rs 43,200 at the end of the first year: \[ 43200 = P \left(1 + \frac{8}{100}\right)^1 \] For the second payment of Rs 34,992 at the end of the second year: \[ 34992 = P \left(1 + \frac{8}{100}\right)^2 \] ### Step 6: Calculate the Values Calculate \( 1 + \frac{8}{100} = 1.08 \). Now, we can rewrite the equations: 1. \( 43200 = P \cdot 1.08 \) 2. \( 34992 = P \cdot (1.08)^2 = P \cdot 1.1664 \) ### Step 7: Solve for \( P \) From the first equation: \[ P = \frac{43200}{1.08} \] Calculating this gives: \[ P = 40000 \] From the second equation: \[ P = \frac{34992}{1.1664} \] Calculating this gives: \[ P = 30000 \] ### Step 8: Find the Total Principal Now we can find the total principal borrowed: \[ \text{Total Principal} = P \cdot 1.08 + P \cdot 1.1664 \] Calculating this gives: \[ \text{Total Principal} = 40000 + 30000 = 70000 \] ### Final Answer The sum borrowed is Rs 67,037.
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ICSE-COMPOUND INTEREST (USING FORMULA)-EXERCISE 3(E)
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  4. The value of a machine, purchased two years ago, depreciates at the an...

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  5. The value of a machine, purchased two years ago, depreciates at the an...

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  6. Anuj and Rajesh each lent the same sum of money for 2 years at 8% simp...

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  7. Calculate the sum of money on which the compound interest (payable ann...

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  8. A sum of money was invested for 3 years, interest being compounded ann...

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  9. A sum of money is invested at 10% per annum compounded half-yearly. If...

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  10. Rohit borrows Rs 86,000 from Arun for two years at 5% per annum simple...

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  11. The simple interest on a certain sum of money for 3 years at 5% per an...

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  12. Nikita invests Rs 6,000 for two years at a certain rate of interest co...

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  13. Nikita invests Rs 6,000 for two years at a certain rate of interest co...

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  14. Simple interest on a sum of money for 2 years at 4% growth rate is Rs ...

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  15. Find the compound interest to the nearest rupee on Rs 10,800 for 2(1)/...

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  16. The value of a machine, purchased two years ago, depreciates at the an...

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  17. The value of a machine, purchased two years ago, depreciates at the an...

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  18. Anuj and Rajesh each lent the same sum of money for 2 years at 8% simp...

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  19. Calculate the sum of money on which the compound interest (payable ann...

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  20. A sum of money was invested for 3 years, interest being compounded ann...

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  21. A sum of money is invested at 10% per annum compounded half-yearly. If...

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