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A sum of money lent out at C.I. at a cer...

A sum of money lent out at C.I. at a certain rate per annum becomes three times of itself in 8 years. Find in how many years will the money become twenty-seven times of itself at. the same rate of interest p.a.

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To solve the problem step by step, we will use the compound interest formula and the information provided in the question. ### Step 1: Understand the Compound Interest Formula The formula for compound interest is given by: \[ A = P \left(1 + \frac{r}{100}\right)^n \] where: - \( A \) = Amount after time \( n \) - \( P \) = Principal amount (initial sum of money) - \( r \) = Rate of interest per annum - \( n \) = Time in years ### Step 2: Set Up the Equation for the First Scenario According to the question, the amount becomes three times the principal in 8 years. Thus, we can write: \[ A = 3P \] Substituting into the formula, we have: \[ 3P = P \left(1 + \frac{r}{100}\right)^8 \] ### Step 3: Simplify the Equation Dividing both sides by \( P \) (assuming \( P \neq 0 \)): \[ 3 = \left(1 + \frac{r}{100}\right)^8 \] Let’s denote this as Equation (1). ### Step 4: Set Up the Equation for the Second Scenario Now, we need to find out how many years it will take for the amount to become twenty-seven times the principal. Thus, we can write: \[ A = 27P \] Substituting into the formula, we have: \[ 27P = P \left(1 + \frac{r}{100}\right)^n \] ### Step 5: Simplify the Second Equation Dividing both sides by \( P \): \[ 27 = \left(1 + \frac{r}{100}\right)^n \] Let’s denote this as Equation (2). ### Step 6: Relate the Two Equations From Equation (1), we have: \[ \left(1 + \frac{r}{100}\right)^8 = 3 \] From Equation (2), we have: \[ \left(1 + \frac{r}{100}\right)^n = 27 \] Notice that \( 27 = 3^3 \). Therefore, we can express Equation (2) as: \[ \left(1 + \frac{r}{100}\right)^n = \left(\left(1 + \frac{r}{100}\right)^8\right)^3 \] This implies: \[ \left(1 + \frac{r}{100}\right)^n = \left(3\right)^3 \] ### Step 7: Set the Exponents Equal Since the bases are the same, we can set the exponents equal: \[ n = 8 \times 3 \] ### Step 8: Calculate \( n \) Calculating this gives: \[ n = 24 \] ### Final Answer Thus, the money will become twenty-seven times of itself in **24 years**. ---
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ICSE-COMPOUND INTEREST (USING FORMULA)-EXERCISE 3(B)
  1. The difference between simple interest and compound interest on a cert...

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  2. A sum of money, invested at compound interest, amounts to Rs 19,360 in...

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  3. A sum of money lent out at C.I. at a certain rate per annum becomes th...

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  4. On what sum of money will compound interest (payable annually) for 2 y...

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  5. Kamal and Anand each lent the same sum of money for 2 years at 5% at s...

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  6. Simple interest on a sum of money for 2 years at 4% is Rs 450. Find co...

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  7. Simple interest on a certain sum of money for 4 years at 4% per annum ...

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  8. Compound interest on a certain sum of money at 5% per annum for two ye...

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  9. A certain sum of money amounts to Rs 23,400 in 3 years at 10% per ann...

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  10. Mohit borrowed a certain sum at 5% per annum compound interest and cle...

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  11. The difference between simple interest and compound interest on a cert...

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  12. A sum of money, invested at compound interest, amounts to Rs 19,360 in...

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  13. A sum of money lent out at C.I. at a certain rate per annum becomes th...

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  14. On what sum of money will compound interest (payable annually) for 2 y...

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  15. Kamal and Anand cach lent the same sum of money for 2 years at 5% at s...

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  16. Simple interest on a sum of money for 2 years at 4% is Rs 450. Find co...

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  17. Simple interest on a certain sum of money for 4 years at 4% per annum ...

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  18. Compound interest on a certain sum of money at 5% per annum for two ye...

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  19. A certain sum of money amounts to Rs 23,400 in 3 years at 10% per ann...

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  20. Mohit borrowed a certain sum at 5% per annum compound interest and cle...

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