Home
Class 9
MATHS
A chord CD of a circle, whose centre is ...

A chord CD of a circle, whose centre is O, is bisected at P by a diameter AB.

Given OA = OB = 15 cm and OP = 9 cm. Calculate the lengths of :
AD

Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

A chord CD of a circles, whose centre is O, is bisected at P by a diameter AB. Give 0A = OB = 15 cm and OP = 9 cm. CB

A chord CD of a circles, whose centre is O, is bisected at P by a diameter AB. Give 04 = OB = 15 cm and OP = 9 cm. AD

A chord CD of a circles, whose centre is O, is bisected at P by a diameter AB. Give 04 = OB = 15 cm and OP = 9 cm. CD

Chords AB and CD of a circle when extended meet at point X. Given AB =4 cm, BX=6 cm and XD=6cm, calculate the length of CD.

In the given figure O is the centre of the circle and AB is a tangents at B. If AB = 15 cm and AC = 7.5 cm. Calculate the radius of the circle.

The figure, given below, show a circle with centre O in which diameter AB bisects the chord CD at point E. If CE = ED = 8 cm and EB = 4 cm. Find the radius of the circle.

In the given figure, the diameter CD of a circle with centre 0 is perpendicular to the chord AB. If AB = 8 cm and CM = 2 cm, find the radius of the circle.

In Figure 3, a circle touches all the four sides of a quadrilateral ABCD whose sides are AB = 6 cm, BC = 9 cm and CD = 8 cm. Find the length of side AD.

Chords AB and CD of a circle with centre O, intersect at a point E. If OE bisects angle AED, prove that chord AB = chord CD.