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In the following figure, OABC is a squar...

In the following figure, OABC is a square. A circle is drawn with O as centre which meets OC at P and OA at Q. Prove that :

`triangle OPA = triangle OQC`,

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In the following figure, OABC is a square. A circle is drawn with as centre which meets OC at P and OA at Q. Prove that: Delta OPA ≅ Delta OQC

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