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Three cubes, whose edges are x cm, 8cm a...

Three cubes, whose edges are x cm, 8cm and 10cm respectively, are melted and recasted into a single cube of edge 12cm. Find 'x'

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To solve the problem, we need to find the value of \( x \) given that three cubes with edges \( x \) cm, 8 cm, and 10 cm are melted and recast into a single cube with an edge of 12 cm. ### Step-by-step Solution: 1. **Calculate the Volume of Each Cube:** - The volume of the first cube (edge \( x \) cm) is given by: \[ V_1 = x^3 \text{ cm}^3 \] - The volume of the second cube (edge 8 cm) is: \[ V_2 = 8^3 = 512 \text{ cm}^3 \] - The volume of the third cube (edge 10 cm) is: \[ V_3 = 10^3 = 1000 \text{ cm}^3 \] 2. **Calculate the Total Volume of the Three Cubes:** - The total volume of the three cubes is: \[ V_{total} = V_1 + V_2 + V_3 = x^3 + 512 + 1000 \] - Simplifying this gives: \[ V_{total} = x^3 + 1512 \text{ cm}^3 \] 3. **Calculate the Volume of the New Cube:** - The volume of the new cube (edge 12 cm) is: \[ V_{new} = 12^3 = 1728 \text{ cm}^3 \] 4. **Set the Total Volume Equal to the Volume of the New Cube:** - According to the problem, the total volume of the three cubes equals the volume of the new cube: \[ x^3 + 1512 = 1728 \] 5. **Solve for \( x^3 \):** - Rearranging the equation gives: \[ x^3 = 1728 - 1512 \] - Calculating the right side: \[ x^3 = 216 \] 6. **Find \( x \):** - To find \( x \), we take the cube root of both sides: \[ x = \sqrt[3]{216} \] - Since \( 6^3 = 216 \), we find: \[ x = 6 \text{ cm} \] ### Final Answer: The value of \( x \) is \( 6 \) cm.
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ICSE-SOLIDS-Exercise 21(A)
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