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For triangle ABC, show that "tan"(B+C)...

For triangle ABC, show that
`"tan"(B+C)/2="cot"A/2`

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For triangle ABC, show that "sin"(A+B)/2="cos"C/2

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If A,B,C are angles of a triangle, prove that "tan "(B+C)/(2)="cot"(A)/(2) .

For triangle ABC, show that : (i) "sin" (A + B)/(2) = "cos" (C)/(2) (ii) "tan" (B + C)/(2) = "cot" (A)/(2)

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In any triangle ABC, show that : 2a sin (B/2) sin (C/2)=(b+c-a) sin (A/2)

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In triangle ABC , prove that tan (B-C)/2 =[( b-c) /(b+c )] cot A/2 , tan (C-A)/2 = [(c-a)/(c+a)]cot B/2 , tan (A-B)/2 = [(a-b)/(a+b)]cot c/2

In triangle ABC, prove that 'tan((B-C)/2)=(b-c)/(b+c)cotA/2 tan(C-A)/2=(c-a)/(c+a)cotB/2 tan(A-B)/2=(a-b)/(a+b)cotC/2

ICSE-COMPLEMENTARY ANGLES-EXERCISE
  1. Evaluate: cos^(2)25^(@)-sin^(2)65^(@)-tan^(2)45^(@)

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  2. Evaluate: ((sin 77^(@))/(cos 13^(@)))^(2)+((cos 77^(@))/(sin 13^(@))...

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  3. Show that: tan 10^(@)tan 15^(@) tan 75^(@)tan 80^(@)=1

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  4. Show that: sin 42^(@)sec 48^(@)+cos 42^(@)cosec 48^(@)=2

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  5. Express the following in terms of angles between 0^(@) and 45^(@) si...

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  6. Express the following in terms of angles between 0^(@) and 45^(@) co...

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  7. Express the following in terms of angles between 0^(@) and 45^(@) co...

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  8. For triangle ABC, show that "sin"(A+B)/2="cos"C/2

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  9. For triangle ABC, show that "tan"(B+C)/2="cot"A/2

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  10. Evaluate : 3(sin 72^(@))/(cos 18^(@))-(sec 32^(@))/(cosec 58^(@))

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  11. Evaluate : 3 cos 80^(@)cosec 10^(@)+2sin 59^(@)sec 31^(@)

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  12. Evaluate : (sin 80^(@))/(cos 10^(@))+sin 59^(@)sec 31^(@)

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  13. Evaluate : tan (55^(@)-A)-cot (35^(@)+A)

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  14. Evaluate : cosec(65^(@)+A)-sec(25^(@)-A)

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  15. Evaluate : 2 (tan 57^(@))/(cot 33^(@))-(cot 70^(@))/(tan 20^(@))-sqr...

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  16. Evaluate : (cot^(2)41^(@))/(tan^(2)49^(@))-2(sin^(2)75^(@))/(cos^(2)...

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  17. Evaluate : (cos 70^(@))/(sin 20^(@))+(cos 59^(@))/(sin31^(@))-8sin^(...

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  18. Evaluate : 14 sin 30^(@)+6cos 60^(@)-5tan 45^(@)

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  19. A triangle ABC is right angled at B, find the value of (secA.sinC-tanA...

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  20. In each case given below, find the value of angle A where 0^(@)leAle90...

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