The graph of `3x+2y=6` meets the x= axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinate of points P and Q.

Answer

To find the coordinates of points P and Q where the graph of the equation \(3x + 2y = 6\) meets the x-axis and y-axis respectively, we can follow these steps:

### Step 1: Find the x-intercept (Point P)
To find the x-intercept, we set \(y = 0\) in the equation \(3x + 2y = 6\).

\[ 3x + 2(0) = 6 \]
\[ 3x = 6 \]
\[ x = \frac{6}{3} = 2 \]

Thus, the coordinates of point P are \((2, 0)\).

### Step 2: Find the y-intercept (Point Q)
To find the y-intercept, we set \(x = 0\) in the equation \(3x + 2y = 6\).

\[ 3(0) + 2y = 6 \]
\[ 2y = 6 \]
\[ y = \frac{6}{2} = 3 \]

Thus, the coordinates of point Q are \((0, 3)\).

### Step 3: Summary of Points
The coordinates of point P (where the graph meets the x-axis) are \((2, 0)\) and the coordinates of point Q (where the graph meets the y-axis) are \((0, 3)\).

### Final Answer:
- Point P: \((2, 0)\)
- Point Q: \((0, 3)\)

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