Find the inclination of the line whose slope is:
`sqrt(3)`

Answer

To find the inclination of the line whose slope is \( \sqrt{3} \), we can follow these steps:

### Step 1: Understand the relationship between slope and inclination
The slope \( m \) of a line is related to its angle of inclination \( \theta \) by the formula:
\[ m = \tan(\theta) \]

### Step 2: Set up the equation
Given that the slope \( m \) is \( \sqrt{3} \), we can write:
\[ \tan(\theta) = \sqrt{3} \]

### Step 3: Identify the angle
We need to find the angle \( \theta \) such that:
\[ \tan(\theta) = \sqrt{3} \]
From trigonometric values, we know that:
\[ \tan(60^\circ) = \sqrt{3} \]

### Step 4: Conclude the result
Thus, we can conclude that:
\[ \theta = 60^\circ \]

### Final Answer
The inclination of the line is \( 60^\circ \).

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