Find the inclination of the line whose slope is:
`1/(sqrt(3))`

Answer

To find the inclination of the line whose slope is \( \frac{1}{\sqrt{3}} \), we can follow these steps:

### Step 1: Understand the relationship between slope and angle
The slope \( m \) of a line is related to the angle of inclination \( \theta \) by the formula:
\[ m = \tan(\theta) \]

### Step 2: Set up the equation
Given that the slope \( m \) is \( \frac{1}{\sqrt{3}} \), we can write:
\[ \tan(\theta) = \frac{1}{\sqrt{3}} \]

### Step 3: Find the angle whose tangent is \( \frac{1}{\sqrt{3}} \)
We need to find \( \theta \) such that:
\[ \tan(\theta) = \frac{1}{\sqrt{3}} \]
From trigonometric values, we know that:
\[ \tan(30^\circ) = \frac{1}{\sqrt{3}} \]

### Step 4: Conclude the value of \( \theta \)
Thus, we can conclude that:
\[ \theta = 30^\circ \]

### Final Answer
The inclination of the line is \( 30^\circ \).

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