Home
Class 9
MATHS
On a graph paper, draw a straight line r...

On a graph paper, draw a straight line represented by the equation `2x-3y+12=0`.
Use the graph drawn to find the values o m and n so that the points (m,-2) and (3,n) lies on the given straight line.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first rewrite the equation in a more manageable form, plot the line on a graph, and then find the values of \( m \) and \( n \) for the given points. ### Step 1: Rewrite the equation The given equation is: \[ 2x - 3y + 12 = 0 \] We can rearrange this equation to express \( y \) in terms of \( x \): \[ 3y = 2x + 12 \] \[ y = \frac{2}{3}x + 4 \] ### Step 2: Find points to plot the line To plot the line, we can choose different values for \( x \) and calculate the corresponding \( y \) values. 1. **For \( x = 0 \)**: \[ y = \frac{2}{3}(0) + 4 = 4 \quad \Rightarrow \quad (0, 4) \] 2. **For \( x = 3 \)**: \[ y = \frac{2}{3}(3) + 4 = 2 + 4 = 6 \quad \Rightarrow \quad (3, 6) \] 3. **For \( x = -6 \)**: \[ y = \frac{2}{3}(-6) + 4 = -4 + 4 = 0 \quad \Rightarrow \quad (-6, 0) \] ### Step 3: Plot the points on graph paper Using the points calculated, we will plot the points \( (0, 4) \), \( (3, 6) \), and \( (-6, 0) \) on the graph paper. After plotting these points, we will draw a straight line through them. ### Step 4: Find \( m \) when \( y = -2 \) To find the value of \( m \) such that the point \( (m, -2) \) lies on the line, we substitute \( y = -2 \) into the equation: \[ -2 = \frac{2}{3}x + 4 \] Rearranging gives: \[ -2 - 4 = \frac{2}{3}x \] \[ -6 = \frac{2}{3}x \] Multiplying both sides by \( \frac{3}{2} \): \[ x = -6 \cdot \frac{3}{2} = -9 \] Thus, \( m = -9 \). ### Step 5: Find \( n \) when \( x = 3 \) Now we find the value of \( n \) such that the point \( (3, n) \) lies on the line. We substitute \( x = 3 \) into the equation: \[ y = \frac{2}{3}(3) + 4 \] Calculating gives: \[ y = 2 + 4 = 6 \] Thus, \( n = 6 \). ### Final Answer The values are: \[ m = -9 \quad \text{and} \quad n = 6 \]
Promotional Banner

Topper's Solved these Questions

  • GRAPHICAL SOLUTION(SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS, GRAPHICALLY)

    ICSE|Exercise EXERCISE 27(B)|17 Videos
  • FACTORISATION

    ICSE|Exercise Exercise 5 (E)|23 Videos
  • ICSE EXAMINATION PAPER 2020

    ICSE|Exercise SECTION - B |21 Videos

Similar Questions

Explore conceptually related problems

Find the value of a so that the point (3,a) lies on the line represented by 2x-3y=5

Find the value of a so that the point (3,a) lies on the line represented by 2x-3y=5.

Find the value of a so that the point (3,\ a) lies on the line represented by 2x-3y+5=0

Find the value of k so that the point (2,5) lies on the line represented by kx + 3y =1 .

Draw graph of linear equations 4x-3y +12 =0. Use graph drawn fo find: x. when y = 4

Draw graph of linear equations 4x-3y +12 =0. Use graph drawn fo find: y " when " x=-3

Draw the graph (straight line) given by equation x-3y=18 . If the straight line drawn passes through the points (m,-5) and (6,n), find the values of m and n.

Draw the graph of the straight line given by equation 5x+6y=30 . Use this graph to find the area of the triangle by this line and the co-ordinate axes.

On the same graph paper, draw the straight lines represented by equations : x= 5 , x+ 5= 0 , y + 3=0 and y = 3 Also find the area and perimeter of the rectangle formed by the intersections of these lines.

Find the equation of the circle which passes through the points (2,3)(4,2) and the centre lies on the straight line y-4x+3=0.