An object is placed at a distance of 15 cm in form of a convex mirror of radius of curvature 10 cm. a.where will the image form? B. Find the magnification m. c. What will be the nature of image real or virtual?

Explanation

Given: R=10cm, `f=R/2=5cm` (positive)
u=15cm (negative ) v=?
a From relation `1/u+1/v=1/f`
`1/v+1/((-15))=1/5`
or `1/v=1/5+1/15=4/15`
or `v=15/4=3.75cm`
Thus the image will form at a distance 3.75 cm behind the mirror.
b. Magnification `m=-v/u=-3.75/((-15))=1/4`
Thus the size fo image is one fourth the size of the object.
c. The image will be virtual and erect.