If the function `f:NtoN` is defined by `f(x)=sqrtx`, then find `(f(25))/(f(16)+f(1))`.

Answer

To solve the problem, we need to evaluate the expression \(\frac{f(25)}{f(16) + f(1)}\) where the function \(f\) is defined as \(f(x) = \sqrt{x}\).

### Step-by-step Solution:

1. **Calculate \(f(25)\)**:
\[ f(25) = \sqrt{25} = 5 \]

2. **Calculate \(f(16)\)**:
\[ f(16) = \sqrt{16} = 4 \]

3. **Calculate \(f(1)\)**:
\[ f(1) = \sqrt{1} = 1 \]

4. **Sum \(f(16)\) and \(f(1)\)**:
\[ f(16) + f(1) = 4 + 1 = 5 \]

5. **Substitute into the expression**:
\[ \frac{f(25)}{f(16) + f(1)} = \frac{5}{5} \]

6. **Simplify the fraction**:
\[ \frac{5}{5} = 1 \]

### Final Answer:
The value of \(\frac{f(25)}{f(16) + f(1)}\) is \(1\).