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Taking the sum's distance as 1.4950xx10^...

Taking the sum's distance as `1.4950xx10^(8)` km and the angle subtended by the sum at a point O on earth as half a degree, find approximately the diameter of the sun.

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To find the diameter of the Sun based on the given information, we can follow these steps: ### Step 1: Understand the problem We are given: - Distance from the Earth to the Sun (D) = \(1.495 \times 10^8\) km - Angle subtended by the Sun at point O on Earth (θ) = 0.5 degrees We need to find the diameter of the Sun (d). ### Step 2: Convert the angle from degrees to radians To use the formula for arc length, we need to convert the angle from degrees to radians. The conversion formula is: \[ \text{radians} = \text{degrees} \times \left(\frac{\pi}{180}\right) \] So, converting 0.5 degrees to radians: \[ \theta = 0.5 \times \left(\frac{\pi}{180}\right) \approx 0.00872665 \text{ radians} \] ### Step 3: Use the arc length formula The arc length (s) can be calculated using the formula: \[ s = D \times \theta \] Where: - \(s\) is the arc length (which is the diameter of the Sun in this case) - \(D\) is the distance from the Earth to the Sun - \(\theta\) is the angle in radians Substituting the values: \[ s = 1.495 \times 10^8 \times 0.00872665 \] ### Step 4: Calculate the arc length Now we perform the multiplication: \[ s \approx 1.495 \times 10^8 \times 0.00872665 \approx 1.304 \times 10^6 \text{ km} \] ### Step 5: Relate arc length to diameter Since the arc length we calculated is actually the diameter of the Sun, we can conclude: \[ d \approx 1.304 \times 10^6 \text{ km} \] ### Final Answer The approximate diameter of the Sun is \(1.304 \times 10^6\) km. ---
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