Slope of a line passing through `P(2,3)` and intersecting the line, `x+y=7` at a distance of `4` units from `P`, is

If a line is passing through p(2,3) which intersects the line x+y=7 at a distance of four units from P. Then the slope of line is

The slope of line passing through A(2, 3), B(4,7)

A line passing through the point P (1, 2) meets the line x+y=7 at the distance of 3 units from P. Then the slope of this line satisfies the equation

A line passing through P(1,2) intersect the line x+y+3=0 in point A such that AP=3sqrt(2) then slope of AP is

Find the equation of a line passing through the intersection of the lines y=2(x-1) and y=3x-5 and which is at a distance of (7)/(sqrt(2)) units from origin.

The slope of the line passing through A(-2,3) is -4/3 .The points on the line that are 10 units away from A are

The equation of the line passing through the point of intersection of the lines 2x+y-4=0, x-3y+5 =0 and lying at a distance of sqrt5 units from the origin, is

The slope of a straight line passing through A(1,2) is 2/3 .The points on the line that are sqrt(13) units away from A are

Find the equations of the line passing through the point of intersection of the lines 3x-2y+4 = 0 , 2x-5y = 1 and whose distance from (2, –1) is 2 .