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A sugar syrup of weight 214.2 g contains...

A sugar syrup of weight 214.2 g contains 34.2 g of sugar `(C_(12)H_(22)O_(11))`. Calculate (i) molal concentration (ii) mole fraction of sugar in the syrup.

Text Solution

Verified by Experts

Amount of water present in syrup
`=214.2-34.2=180g`
`:.` Molal concentration `=(34.2 xx 1000)/(180xx342)=0.555`
Mole fraction `=(34.2//342)/(34.2 //342+180//18)=(0.1)/(0.1+10)=(0.1)/(10.1) `
`=0.0099`
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