Home
Class 12
CHEMISTRY
Two liquids A and B form ideal solutions...

Two liquids A and B form ideal solutions. At 300 K, the vapour pressure of a solution containing 1 mole of A and 3 moles of B is 550 mm Hg . At the same temperature , if one more mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm Hg. The vapour pressures of A and B in their pure states are respectively

Text Solution

Verified by Experts

Let `p_(0)^(0)A and x_(A)` are the vapour pressure and mole fraction of liquid A. `p_(B) and x_(B)` are the vapour pressure and mole fraction of liquid B. Then according to Raboult.s law, total pressure, P is given as:
`P=p_(A)^(0) x_(A)+p_(B)^(0) x_(B)`
For first solution, `x_(A)=(1)/(3+1)=0.25 and x_(B)=(3)/(3+1)=0.75`
`:. 550 m m=p_(A)^(0) xx 0.25 +p_(B)^(0) xx 0.75" "...(i)`
For second solution `x_(B) =(1)/(4+1) = 0.20, x_(B)=(4)/(4+1)=0.8`
`:. 560 m m = p_(A)^(0) xx 0.2 xx p_(B)^(0) xx 0.8 " "...(ii)`
Total number of moles in first and second solution are
`4(=1+3) and 5[=1+(3+1)]`.
Multiply equation (i) by 4 and (ii) by 5 and subtracting, we get
`{:(2200 mm=p_(A)^(0)+3p_(B)^(0)" "...(iii)),(2800mm=p_(A)^(0)+4p_(B)^(0)" "...(iv)),(ul(-" "-" "-" ")),(-600mm=-p_(B)^(0)):}`
`:.p_(B)^(0)=600`mm.
Substituting the value of `p_(B)^(0)=600` mm in equation (iii), we get 2200 mm `=p_(A)^(0)+3xx600` mm
`:.p_(A)^(0)=2200-1800=400` mm.
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    ICSE|Exercise Follow up Problems |58 Videos

  • SOLUTIONS

    ICSE|Exercise EXERCISE (PART-I Objective Questions)|26 Videos

  • SOLID STATE

    ICSE|Exercise ISC EXAMINATION QUESTIONS PART-I (Numerical Problems)|6 Videos

  • SOME IMPORTANT ORGANIC NAME REACTIONS

    ICSE|Exercise Questions |278 Videos

Similar Questions

Explore conceptually related problems

Two liquids A and B form ideal solution. At 300 K , the vapour pressure of a solution containing 1 mole of A and 3 moles of B is 550 mm of Hg. At the same temperature, if one more mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. Determine the vapour pressure of a and B in their pure states.

Two liquids A and B form an ideal solution. At 300 K , the vapour pressure of a solution containing 1 mol of A and 3 mol fo B is 550 mm Hg . At the same temperature, if 1 mol more of B is added to this solution, the vapour pressure of the solution increases by 10 mm Hg . Determine the vapour pressure of A and B in their pure states.

The liquid A and B form ideal solutions. At 300 K, the vapour pressure of solution containing 1 mole of A and 3 mole of B is 550 mm Hg. At the same temperature, if one more mole of B is added to this solution, the vapour pressure of the solution increases by 10 mm Hg. Determine the vapour pressure of A and B in their pure states (in mm Hg).

At 27^(@)C .the vapour pressure of an ideal solution containing 1 mole of A and 1 mole and B is 500 mm of Hg . At the same temperature, if 2 mol of B is added to this solution the vapour pressure of solution increases by 50 mm of Hg . The vapour pressure of A and B in their pure states is respectively.

At 300 K , the vapour pressure of an ideal solution containing one mole of A and 3 mole of B is 550 mm of Hg . At the same temperature, if one mole of B is added to this solution, the vapour pressure of solution increases by 10 mm of Hg . Calculate the V.P. of A and B in their pure state.

Two liquid X and Y form an ideal solution. At 300K vapour pressure of the solution containing 1 mol of X and 3 mol of Y 550 mm Hg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mmHg) of X and Y in their pure states will be , respectively :

At 300 K, the vapour pressure of an ideal solution containing 1 mole of A and 3 moles of B is 500 mm Hg. At the same temperature, 2 moles of B are added to this solution. The vapour pressure of solution increases by 10% of the original vapour pressure. Correct statements about the vapour pressure are

Vapour pressure of solution obtained by mixing 1 mole of n hexane and 3 mole of n-heptane is 550 mm Hg . On mixing 1 mole n-heptane, vapour pressure of solution increases by 10mm Hg. Find the vapour pressure of pure n-heptane

Vapour pressure of solution obtained by mixing 1 mole of n hexane and 3 mole of n-heptane is 550 mm Hg . On mixing 1 mole n-heptane, vapour pressure of solution increases by 10mm Hg. Find the vapour pressure of pure n-heptane

Two liquids A and B form an ideal solution of 1 mole of A and x moles of B is 550 mm of Hg. If the vapour pressures of pure A and B are 400 mm of Hg nd 600 mm of Hg respectively. Then x is-