Home
Class 12
CHEMISTRY
The freezing point of nitrobenzene is 27...

The freezing point of nitrobenzene is 278.8 K. A 0.25 molal solution of a substance (molecular weight : 120) in nitrobenzene has a freezing point of 276.8 K. Calculate the molal depression constant of nitrobenzene.

Text Solution

AI Generated Solution

To solve the problem, we will use the formula for freezing point depression, which is given by: \[ \Delta T_f = K_f \cdot m \] Where: - \(\Delta T_f\) = change in freezing point ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    ICSE|Exercise Follow up Problems |58 Videos
  • SOLUTIONS

    ICSE|Exercise EXERCISE (PART-I Objective Questions)|26 Videos
  • SOLID STATE

    ICSE|Exercise ISC EXAMINATION QUESTIONS PART-I (Numerical Problems)|6 Videos
  • SOME IMPORTANT ORGANIC NAME REACTIONS

    ICSE|Exercise Questions |278 Videos

Similar Questions

Explore conceptually related problems

The normal freezing point of nitrobenzene (C_(6)H_(5)NO_(2)) is 278.82K . 0.25 molal solution of a certain solute in nitrobenzene causes a freezing point depression of 2 degrees. Calculate the value of K_(f) for nitrobenzene.

The normal freezing point of nitrobenzne (C_(6)H_(5)NO_(2)) is 278.82 K.A 0.25 m solution of solute A in nitrobenzene decreases the freezing point to 276.82 K. The value of K_(f) for nitrobenzene is

Cryoscopic constant for benezene is 4.9 K kg mol^(-1) . Freezing point of benezene is 278.6 K. 4 grams of benzoic acid when dissolved in 50 g of benezene, the freezing point is 276.98K. Calculate the extent of association of benzoic acid in benezene .

A 0.075 molal solution of monobasic acid has a freezing point of -0.18^(@)C . Calculate K_(a) for the acid , (k_(f)=1.86)

Read the following paragraph and answer the question given below: Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02 mol fraction of acetic acid in benzene is 277.4 K. The molal cryoscopic constant of benzene in K "molality"^(-1) is

Dissolution of 1.5 g of a non-volatile solute (mol.wt.=60) in 250 g of a solvent reduces its freezing point by 0.01^(@)C . Find the molal depression constant of the solvent.

The freezing point of a 0.05 molal solution of a non-electrolyte in water is: ( K_(f) = 1.86 "molality"^(-1) )

The freezing point of nitrobenzene is 3^(@)C . When 1.2 g of chloroform (mol. Wt. =120) is dissolved in 100 g of nitrobenzene, freezing point will be 2.3^(@)C . When 0.6 g of acetic acid is dissolved in 100 g of nitrobenzene, freezing point of solution is 2.64^(@)C . If the formula of acetic acid is (CH_(2)O)_(n) , find the value of n.

What will be the freezing point of a 0.5 m KCl solution ? The molal freezing point constant of water is 1.86^@C m^(-1) .

2.71 g of a substance dissolved in 55 g of CH2COOH produced a depression in the freezing point of 0.618 o C. Calculate the molecular weight of the substance. (Kf=3.85)