Home
Class 12
CHEMISTRY
The weights of solutes present in two is...

The weights of solutes present in two isotonic solutions A and B are in the ratio 2:3. If the solutes are non-electrolytes, how are their molecular weights related ?

Text Solution

AI Generated Solution

To solve the problem, we need to understand the relationship between the weights of solutes in isotonic solutions and their molecular weights. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Concept of Isotonic Solutions Isotonic solutions are solutions that have the same osmotic pressure. This means that the concentration of solute particles in both solutions is equal. ### Step 2: Use the Formula for Osmotic Pressure The osmotic pressure (π) of a solution can be expressed using the formula: \[ \pi = CRT \] ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    ICSE|Exercise Follow up Problems |58 Videos
  • SOLUTIONS

    ICSE|Exercise EXERCISE (PART-I Objective Questions)|26 Videos
  • SOLID STATE

    ICSE|Exercise ISC EXAMINATION QUESTIONS PART-I (Numerical Problems)|6 Videos
  • SOME IMPORTANT ORGANIC NAME REACTIONS

    ICSE|Exercise Questions |278 Videos

Similar Questions

Explore conceptually related problems

The weight of solute present in 200mL of 0.1M H_(2)SO_(4) :

The rates of diffusion of gases A and B of molecular weight 36and 64 are in the ratio

10% solution of urea is isotonic with 6% solution of a non-volatile solute X.What is the molecular mass of solute X ?

Equal weights of two substances X and Y are dissolved in equal volumes of water. The osmotic pressure of the solution containing Y is five times the osmotic pressure of the solution containing X. What is the molecular weight of X if that of Y is 60?

Why does the solution of an electrolyte conduct eletricity but that an non - electrolyte does not ?

The vapour pressure of a solution of a non-volatile electrolyte B in a solvent A is 95% of the vapour pressure of the solvent at the same temperature. If the molecular weight of the solvent is 0.3 times, the molecular weight of solute, the weight ratio of the solvent and solute are:

3% solution of glucose is isotonic with 1% solution of a non-volatile non-electrolyte substance. The molecular mass of the substance would be

A 10% solution of urea is isotonic with 20% solution of 'x' at same temperature. Calculate molecular weight of x .

A solution containing 8.6g per dm^(3) of urea (mol. wt. 60) was found to be isotonic with a 5 per cent solution of an organic non volatile solute. Calculate molecular weight of the latter.

The freezing point of a 3% (by weight) aqueous solution of A is equal to the freezing point of 9% (by weight) aqueous solution of B . If the molecular weight of A is 60 , then the molecular weight of B will be a 191 ,b. 90 , c. 45 , d. 20