Home
Class 12
CHEMISTRY
Calculate the freezing point of an aqueo...

Calculate the freezing point of an aqueous solution containing 10.50 g of `MgBr_(2)` in 200 g of water (Molar mass of `MgBr_(2) = 184g`). (`K_(f)` for water `= 1.86" K kg mol"^(-1)`)

Text Solution

Verified by Experts

`MgBr_(2)` being an ionic compound ionizes as:
`MgBr_(2) hArr Mg^(2+) +2Br^(-)`
`:. .i.=1+2=3`
`DeltaT_(f)=iK_(f) xx m =3 xx 1.86 xx m`
`m=("Weight of solute")/("Molar mass of solute") xx (100)/("Weight of solvent")`
`:. DeltaT_(f)=(3 xx 1.86 xx 10.50 xx 1000)/(184 xx 200)=1.59^(@)`
`:.`F.P. of solution `=273.15-1.59=271.56K`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    ICSE|Exercise Follow up Problems |58 Videos
  • SOLUTIONS

    ICSE|Exercise EXERCISE (PART-I Objective Questions)|26 Videos
  • SOLID STATE

    ICSE|Exercise ISC EXAMINATION QUESTIONS PART-I (Numerical Problems)|6 Videos
  • SOME IMPORTANT ORGANIC NAME REACTIONS

    ICSE|Exercise Questions |278 Videos

Similar Questions

Explore conceptually related problems

(a) Differentiate between molarity and molality for a solution. How does a change in temperature influence their values ? (b) Calculate the freezing point of an aqueous solution containing 10.50g of MgBr_(2) in 200g of water. (Molar mass of MgBr_(2)=184g ) ( K_(f) for waer =1.86K kg "mol"^(-1) )

What would be the freezing point of aqueous solution containing 17 g of C_(2)H_(5)OH in 100 g of water (K_(f) H_(2)O = 1.86 K mol^(-1)kg) :

Calculate the freezing point of a solution containing 8.1 g of HBr in 100g of water, assuming the acid to be 90% ionized. [Given : Molar mass Br = 80 g/mol, K_(f) water = 1.86 K kg/mol].

The boiling point of pure water is 373 K. calculate the boiling point of an aqueous solution containing 18 g of glucose (M.W. = 180) in 100g of water. Molal elevation constant of water is 0.52 K kg "mol"^(-1) .

What should be the freezing point of aqueous solution containing 17g of C_(2)H(5)OH is 1000g of water ( K_(f) for water = 1.86 deg kg mol^(-1) )?

Calculate the freezing point of a solution containing 0.5 g KCl (Molar mass = 74.5 g/mol) dissolved in 100 g water, assuming KCl to be 92% ionized. K_(f) of water = 1.86 K kg/mol.

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )

The freezing point of a solution containing 0.1g of K_3[Fe(CN)_6] (Mol. Wt. 329) in 100 g of water ( K_f =1.86K kg mol^(−1) ) is:

Calculate the freezing point of an aqueous solution containing 10.5g of Magnesium bromide in 200 g of water, assuming complete dissociation of Magnesium bromide. (Molar mass of magnesium bromide =184 g mol ^(-1) , for water =1.86K kg mol^(-) ).