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Calculate the freezing point depression ...

Calculate the freezing point depression expected for `0.0711` m aqueous solution of `Na_(2)SO_(4)` . If this solution actually freezes at `-0.320 ^(@)C` , what would be the value of Van't Hoff factor ?
(`K_(f)` for water is `1.86 ^(@)C mol^(-1)`) .

Text Solution

Verified by Experts

If there is no dissociation, `DeltaT_(f)=K_(f) xx m`
`:. DeltaT_(f)=1.86 xx 0.0711 = 0.132^(@)`
Observed depression in freezing point `= 0.320^(@)`
van.t Hoff factor (i)
`=("Observed value of colligative property")/("Calculated value of colligative property")=(0.320)/(0.132)`
`=2.424`
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