Calculate the molarity of each of the following solutions: (a) 30 g of `Co(NO_(3))_(2).6H_(2)O` in 4.3 L of solution (b) 30 mL of 0.5 M `H_(2)SO_(4)` diluted to 500 mL.

Answer

0.022 M

Explanation

Molar mass of `Co(NO_(3))_(2).6H_(2)O`
`= 58.7+2 (14+3 xx16) +6 (2+16)=310.7" g mol"^(-1)`
Number of moles in 30g of `CO(NO_(3))_(2).6H_(2)O`
`=("Mass")/("Molar mass")=(30g)/(310.7"g mol"^(-1))=0.0966`
Volume of solution = 4.3L
Molarity of solution
`=("Number of moles of solute")/("Volume of solution in litre")=(0.0966)/(4.3L)=0.022M`