What will be the molarity of 30 mL of 0.5 M `H_2SO_4` solution diluted to 500 mL ?

Answer

0.03 M

Explanation

1000 mL of 0.5 M `H_(2)SO_(4)` contain `H_(2)SO_(4)=0.5` mol,
30 mL of 0.5 `MH_(2)SO_(4)` contain `H_(2)SO_(4)`
`=(0.5)/(1000) xx 30"mol"=0.015` mol
Volume of solution =500 mL = 0.5 L,
Molarity of solution
`=("Number of moles of "H_(2)SO_(4))/("Volume of "H_(2)SO_(4)" in litre")=(0.015)/(0.5)=0.03M`