A commercially available sample of `H_(2)SO_(4)` is 15% `H_(2)SO_(4)` by mass. Its density is 1.10g `cm^(-3)` . Calculate its molarity.

Answer

1.68 M

Explanation

Mol. mass of `H_(2)SO_(4)=98`
Weight of `H_(2)SO_(4)` per 100 g of solution = 15 g
Gram moles of `H_(2)SO_(4)=(15)/(98)`
Volume of solution `=("Mass")/("Density")=(100)/(1.10)=90.9mL`
`:.` Molarity of `H_(2)SO_(4)=("Moles of "H_(2)SO_(4))/("Volume of solution (mL)") xx 1000`
`=(15xx1000)/(98.90.9)=1.68M`.