Calculate the amount of benzoic acid (C(...

Calculate the amount of benzoic acid `(C_(6)H_(5)COOH)` required for preparing 250 mL of 0.15 M solution in methanol.

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The correct Answer is:

4.575 g

Molecular mass of benzoic acid `(C_(6)H_(5)COOH)`
`=12xx7+1xx6+2xx16=122"g mol"^(-1)`
Amount of benzoic acid in 1000 mL of 1 M solution = 122g
Amount of benzoic acid in 250 mL of 0.15M solution
`=(122)/(1000) xx 250xx0.15=4.575g`

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