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The molality and molarity of a H(2)SO(4)...

The molality and molarity of a `H_(2)SO_(4)` solution are `94.13` and `11.12` respectively. Calculate the density of the solution.

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To calculate the density of the `H₂SO₄` solution given its molality and molarity, we can use the following formula: \[ \text{Density} = \frac{\text{Molarity}}{\text{Molality}} + \frac{\text{Molecular Weight}}{1000} \] ### Step 1: Identify the values - Molarity (M) = 11.12 mol/L - Molality (m) = 94.13 mol/kg - Molecular weight of `H₂SO₄` = 98 g/mol ### Step 2: Calculate the density using the formula First, we need to calculate the second part of the formula, which is the molecular weight divided by 1000: \[ \frac{\text{Molecular Weight}}{1000} = \frac{98 \text{ g/mol}}{1000} = 0.098 \text{ g/mL} \] Now, we can substitute the values into the density formula: \[ \text{Density} = \frac{11.12}{94.13} + 0.098 \] Calculating the first part: \[ \frac{11.12}{94.13} \approx 0.118 \] Now, adding this to the second part: \[ \text{Density} = 0.118 + 0.098 = 0.216 \text{ g/mL} \] ### Step 3: Convert to grams per milliliter Since the density is typically expressed in grams per milliliter (g/mL), we can keep it as it is. ### Final Answer The density of the `H₂SO₄` solution is approximately **1.20 g/mL**. ---

To calculate the density of the `H₂SO₄` solution given its molality and molarity, we can use the following formula: \[ \text{Density} = \frac{\text{Molarity}}{\text{Molality}} + \frac{\text{Molecular Weight}}{1000} \] ### Step 1: Identify the values - Molarity (M) = 11.12 mol/L ...
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