We have three aqueous solutions of NaCl lebelled as'A' , 'B' and 'C' with concentrations 0.1 M, 0.01 M and 0.001 M respectively. The value of van't Hoff factor for these solution will be in the order……….

Options

A. `i_(A) lt i_(B) lt i_(C )`
B. `i_(A) gt i_(B) gt i_(C )`
C. `i_(A)=i_(B)=i_(C )`
D. `i_(A) lt i_(B) gt i_(C )`

Answer

C

Explanation

NaCl being a strong electrolyte, ionizes completely in dilute solution `(alpha = 1)`. Therefore, the value of van.t Hoff factor does not change with the change in molar concentration of NaCl. Therefore, `i_(A) = i_(B) = i_(C )`.