The osmotic pressure of 0.25 M urea solution is 2.67 atm. What will be the osmotic pressure of a 0.25 M solution of potassium sulfate?

Explanation

To find the osmotic pressure of a 0.25 M solution of potassium sulfate (K2SO4), we can use the formula for osmotic pressure, which is given by:

\[ \pi = iCRT \]

Where:
- \(\pi\) = osmotic pressure
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