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0.70 g of an organic compound when disso...

0.70 g of an organic compound when dissolved in 32 g of acetone produces an elevation of 0.25°C in the boiling point. Calculate the molecular mass of organic compound. `(K_(b)" for acetone" = 1.72" K kg mol"^(-1))`.

Text Solution

Verified by Experts

Mass of acetone `(W_(1)) = 32 g`
Mass of organic compound `(W_(2)) = 0.70 g`
`DeltaT_(b)=0.25^(@)C, K_(b)=1.72"K kg mol"^(-1)`
`DeltaT_(b)=K_(b) xx m=K_(b) xx (1000 W_(2))/(W_(1)M_(2))`
or `M_(2)=(K_(b) xx 1000 xx W_(2))/(DeltaT_(b) xx W_(1))=(1.72 xx 1000 xx 0.70)/(0.25 xx 32)`
`=150.5" g mol"^(-1)`
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