`sin^2((2pi)/3)+cos^2((5pi)/6)-tan^2((3pi)/4)`

Prove that: (sin^(2)pi)/(6)+(cos^(2)pi)/(3)-tan^(2)(pi)/(4)=-(1)/(2)

" 1.Prove that : "sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)(pi)/(4)=-(1)/(2)

The value of 2sin^(2)((pi)/(3))-cos^(2)((pi)/(6))+tan^(2)(pi/6) is equal to ....

Find the value of the sin^(2)((pi)/(6))+cos^(2)((pi)/(3))-tan^(2)((pi)/(4))

Prove that (a) sin^(2)(pi/6) + cos^(2)( pi/3) - tan^(2)(pi/4) = -1/2 (b) sin((8pi)/3) cos((23pi)/6) + cos((13pi)/3) sin((35pi)/6) = 1/2

(sec^(2)(pi)/(4)-cot^(2)(pi)/(4))/(sin^(2)(pi)/(3)+cos^(2)(pi)/(6))+(sin^(2)(pi)/(2)-cos^(2)(pi)/(3))/((1)/(4)tan^(2)(pi)/(6))=9(2)/(3)

If [[sin((pi)/(2)), cos((pi)/(3))], [2tan((pi)/(4)), 2k]] is not invertible, then k=

sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)-(1)/(2)(pi)/(4)=-(1)/(2)

"sin"^(2)(pi)/(6)+"cos"^(2)(pi)/(3)-"tan"^(2)(pi)/(4)+(1)/(2) is:

"sin"^(2)(pi)/(6)+"cos"^(2)(pi)/(3)-"tan"^(2)(pi)/(4)+(1)/(2) is: