Two superimposig waves are represented by equation ` y_1=2 sin 2 pi ( 10t-0.4x) and y_2=4 sin2 pi ( 20 t- 0.8x)` . The ratio of `l_("max") " to " l_("min")` is

The superposing waves are represented by the following equations : y_(1) 5 sin 2 pi (10 t-0.1 x ), y_(2)=10 sin 2 pi (20t -0.2 x) Ratio of intensities (I_("max"))/(I_("min")) will be

Two waves are represented by the following equations : y_1 =5 sin 2pi (10 t-0.1x) and y_2=10 sin 2pi (20 t-0.2 x) Ratio of intensities I_2//I_1 will be.

Two sound waves are represented by y_(1) = 10 sin 2pi (50 t- 0.5x), y_(2) = 30 sin 2pi (60t - 0.8x) The ratio of their intensities ((I_(1))/(I_(2))) is

Two simple harmonic motions are represented by the equations y_(1)=2(sqrt(3)cos3 pi t+sin3 pi t) and y_(2)=3sin(6 pi t+pi/6)

A wave is represented by the equation y=10 sin 2pi (100 t-0.02x)+ 10 sin 2pi (100t +0.02 x). The maximum amplitude and loop length are respectively.

Two simple harmonic motions are represented by the equations : x_1 = 5 sin (2 pi t + pi//4 ) , x_2 = 5^(2) (sin2 pi t + cos2 pi t) What is the ratio of their amplitudes ?

Two simple harmonic waves are represented by the equations given as y_(1) = 0.3 sin(314 t - 1.57 x) y_(2) = 0.1 sin(314 t - 1.57x + 1.57) where x, y_(1) and y_(2) are in metre and t is in second, then we have

If two SHMs are represented by equations y_(1) = 5 sin (2pi t + pi//6) and y_(2) = 5 [sin (3pi) + sqrt3 cos (3pi t)] . Find the ratio of their amplitudes.

The transverse wave represented by the equation y = 4 "sin"((pi)/(6)) "sin"(3x - 15 t) has