A, B, C and D illustrate the properties of sulphuric acid whether dilute or concentrated.
Choose the property (A, B, C, or D) depending on which one is relevant to each of the following:
Action of concentrated sulphuric acid on sulphur. 

Options

A. A = Typical acid property
B. B = Nonvolatile acid
C. C = Oxidising agent
D. D = Dehydrating agent

Answer

To determine the property of concentrated sulphuric acid when it acts on sulphur, we can follow these steps:

### Step 1: Identify the Reaction
Concentrated sulphuric acid (H₂SO₄) reacts with sulphur (S). We need to write the chemical equation for this reaction.

### Step 2: Write the Chemical Equation
The reaction can be represented as follows:
\[ \text{S} + \text{H}_2\text{SO}_4 \rightarrow \text{SO}_2 + \text{H}_2\text{O} \]

### Step 3: Balance the Chemical Equation
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides. The balanced equation is:
\[ 3\text{S} + 2\text{H}_2\text{SO}_4 \rightarrow 3\text{SO}_2 + 2\text{H}_2\text{O} \]

### Step 4: Analyze the Reaction
In this reaction, sulphur (S) is oxidized to sulphur dioxide (SO₂). This indicates that concentrated sulphuric acid is acting as an oxidizing agent.

### Step 5: Choose the Relevant Property
From the options given (A, B, C, D):
- A: Typical acidic property
- B: Nonvolatile acid
- C: Oxidizing agent
- D: Dehydrating agent

Since concentrated sulphuric acid oxidizes sulphur to sulphur dioxide, the relevant property is **C: Oxidizing agent**.

### Final Answer
The property of concentrated sulphuric acid when it acts on sulphur is **C: Oxidizing agent**.

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