A, B, C and D illustrate the properties of sulphuric acid whether dilute or concentrated.Choose the role played by sulphuric acid as A, B, C, or D which is responsible for the reactions. Some role(s) may be repeated.
`S + H_2SO_4(conc.) to 3SO_2 + 2H_2O`

Options

A. A = Typical acid property
B. B = Nonvolatile acid
C. C = Oxidising agent
D. D = Dehydrating agent

Answer

To solve the question regarding the role of sulfuric acid in the reaction of sulfur with concentrated sulfuric acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**: The reaction given is:
\[ S + H_2SO_4(\text{conc.}) \rightarrow 3SO_2 + 2H_2O \]
Here, sulfur (S) reacts with concentrated sulfuric acid (H₂SO₄) to produce sulfur dioxide (SO₂) and water (H₂O).

2. **Determine the Role of Sulfuric Acid**: In this reaction, sulfur is being converted to sulfur dioxide. This indicates that sulfur is undergoing oxidation.

3. **Recognize the Oxidizing Agent**: An oxidizing agent is a substance that causes another substance to be oxidized and itself gets reduced. In this case, concentrated sulfuric acid (H₂SO₄) is responsible for oxidizing sulfur (S) to sulfur dioxide (SO₂).

4. **Select the Correct Property**: From the options provided (A, B, C, D), we need to identify which property corresponds to the oxidizing action of sulfuric acid. The properties are:
- A: Typical acidic property
- B: Non-volatile acid
- C: Oxidizing agent
- D: Dehydrating agent

Since sulfuric acid acts as an oxidizing agent in this reaction, we can conclude that the correct role played by sulfuric acid in this reaction is **C: Oxidizing agent**.

### Final Answer:
The role played by sulfuric acid in the reaction \( S + H_2SO_4(\text{conc.}) \rightarrow 3SO_2 + 2H_2O \) is **C: Oxidizing agent**.

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