The reaction `KCl + H_2SO_4 (conc.) rarr KHSO_4 + HCl` demonstrates which nature of sulphuric acid?

Options

A. Acidic
B. Nonvolatile
C. Oxidising
D. Dehydrating

Answer

To determine the nature of sulfuric acid demonstrated by the reaction \( KCl + H_2SO_4 (conc.) \rightarrow KHSO_4 + HCl \), we can analyze the reaction step by step.

### Step 1: Write the Reaction
The given reaction is:
\[ KCl + H_2SO_4 (conc.) \rightarrow KHSO_4 + HCl \]

### Step 2: Identify the Reactants and Products
In this reaction:
- **Reactants**: Potassium chloride (KCl) and concentrated sulfuric acid (H2SO4).
- **Products**: Potassium bisulfate (KHSO4) and hydrochloric acid (HCl).

### Step 3: Analyze the Nature of Sulfuric Acid
Sulfuric acid (H2SO4) is a strong acid and is known for its properties:
- It is a non-volatile acid due to its high boiling point (approximately 356°C).
- When it reacts with potassium chloride (KCl), it displaces the hydrochloric acid (HCl), which is a volatile acid.

### Step 4: Conclusion
The reaction demonstrates the **non-volatile nature** of sulfuric acid. This is because sulfuric acid remains in the reaction mixture while hydrochloric acid, which is volatile, is released as a gas.

### Final Answer
The reaction \( KCl + H_2SO_4 (conc.) \rightarrow KHSO_4 + HCl \) demonstrates the **non-volatile nature of sulfuric acid**.

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