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The sum of first 9 terms of the series :...

The sum of first 9 terms of the series `:`
`( 1^(3))/( 1) + ( 1^(3) + 2^(3))/( 1+ 3) + ( 1^(3) + 2^(3) + 3^(3))/( 1+ 3+ 5)+"........."` is `:`

A

`(n+1)/(4)`

B

`(n(n+1))/(2)`

C

` ((n+1)^(2))/(6)`

D

` ((n+1)^(2))/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
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HIMALAYA PUBLICATION-MATHEMATICAL INDUCTION AND SUMMATION OF SERIES-Question Bank
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  3. The sum of first 9 terms of the series : ( 1^(3))/( 1) + ( 1^(3) + 2...

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  4. (1)/(1 . 4)+(1)/(4 . 7)+(1)/(7 . 10)+.. .. .. ..=

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  7. (1)/(2 !)+(2)/(3 !)+(3)/(4 !)+.. .. to n terms =

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  8. Sum of 10 terms of the series (3)/(1^(2))+(5)/(1^(2)+2^(2))+(7)/(1+2...

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  9. If the sum of n terms of the series : (1)/( 1^(3)) +( 1+2)/( 1^(3) +...

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  10. Sum of 25 terms of the series 1 . 3+2 . 5+3 . 7+.., is

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  11. If the natural numbers are divided into the groups (1),(2,3),(4,5,6),(...

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  12. If (sum n^(3))(sum n)=(sum n^(2))^(2), then

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  13. 4^(3)+5^(3)+6^(3)+.. .+10^(3)=

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  14. 3+5+7+ …..to n^(th) term is

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  19. The sum of cubes of three successive natural numbers is divisible by

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  20. Product of 4 consecutive natural numbers is divisible by

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