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If the equation ax^(2) + 2bx - 3c = 0 ha...

If the equation `ax^(2) + 2bx - 3c = 0` has non-real roots and `((3c)/(4)) lt (a + b)` , then c is always :

A

(-1,1)

B

(0,1)

C

(0, oo)

D

(-oo, 0)

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The correct Answer is:
D
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