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In a race the probabilities of A and B w...

In a race the probabilities of A and B winning the race are `1/3 and 1/6` respectively. Find the probability of neighter of them winning the race.

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To find the probability of neither A nor B winning the race, we can follow these steps: ### Step 1: Identify the probabilities of A and B winning We are given: - Probability of A winning, \( P(A) = \frac{1}{3} \) - Probability of B winning, \( P(B) = \frac{1}{6} \) ### Step 2: Calculate the probability of either A or B winning To find the probability of either A or B winning, we can use the formula for the union of two mutually exclusive events: \[ P(A \cup B) = P(A) + P(B) \] Substituting the values we have: \[ P(A \cup B) = \frac{1}{3} + \frac{1}{6} \] ### Step 3: Find a common denominator To add the fractions, we need a common denominator. The least common multiple of 3 and 6 is 6. - Convert \( \frac{1}{3} \) to sixths: \[ \frac{1}{3} = \frac{2}{6} \] - Now we can add: \[ P(A \cup B) = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} \] ### Step 4: Calculate the probability of neither A nor B winning The probability of neither A nor B winning can be found using the complement rule: \[ P(\text{neither A nor B}) = 1 - P(A \cup B) \] Substituting the value we found: \[ P(\text{neither A nor B}) = 1 - \frac{1}{2} = \frac{1}{2} \] ### Final Answer The probability of neither A nor B winning the race is: \[ \frac{1}{2} \] ---
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