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In the following nuclear reaction, calcu...

In the following nuclear reaction, calculate the energy released in MeV :
`""_(1)^(2)H+""_(1)^(2)Hto""_(2)^(3)He+""_(0)^(1)n`
Given that : Mass of `""_(1)^(2)H=2.015u`
Mass of `""_(2)^(3)He=3.017u`
Mass of `""_(0)^(1)n=1.009u`
What is the name of this reaction?

Text Solution

AI Generated Solution

To calculate the energy released in the given nuclear reaction, we will follow these steps: ### Step 1: Identify the masses of reactants and products The nuclear reaction is: \[ \text{ }_{1}^{2}\text{H} + \text{ }_{1}^{2}\text{H} \rightarrow \text{ }_{2}^{3}\text{He} + \text{ }_{0}^{1}\text{n} \] - Mass of \( \text{ }_{1}^{2}\text{H} \) (Deuterium) = 2.015 u - Mass of \( \text{ }_{2}^{3}\text{He} \) (Helium-3) = 3.017 u ...
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