A body has a positive charge of `8xx10^(-19)C`. It has :

Options

A. an excess of 5 electrons
B. a deficiency of 5 electrons
C. an excess of 8 electrons
D. a deficiency of 8 electrons

Explanation

To solve the problem, we need to determine how many electrons are deficient in a body that has a positive charge of \(8 \times 10^{-19} \, \text{C}\).

### Step-by-Step Solution:

1. **Understanding Charge**:
A positive charge indicates a deficiency of electrons. Each electron carries a charge of approximately \( -1.6 \times 10^{-19} \, \text{C} \).

2. **Setting Up the Equation**:
The total positive charge of the body can be expressed as:
\[ Q = n \cdot e \]
where:
- \( Q \) is the total positive charge (\(8 \times 10^{-19} \, \text{C}\)),
- \( n \) is the number of electrons missing,
- \( e \) is the charge of one electron (\(1.6 \times 10^{-19} \, \text{C}\)).

3. **Rearranging the Equation**:
We can rearrange the equation to find \( n \):
\[ n = \frac{Q}{e} \]

4. **Substituting the Values**:
Now, substituting the known values into the equation:
\[ n = \frac{8 \times 10^{-19} \, \text{C}}{1.6 \times 10^{-19} \, \text{C}} \]

5. **Calculating \( n \)**:
Performing the division:
\[ n = \frac{8}{1.6} = 5 \]

6. **Conclusion**:
Therefore, the body has a deficiency of 5 electrons.

### Final Answer:
The body has a deficiency of 5 electrons.