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Three capacitors C(1)=6muF,C(2)=12muF an...

Three capacitors `C_(1)=6muF,C_(2)=12muF` and `C_(3)=20muF` are connected to a 100 V battery, as shown in figure below:

(i) Charge on each plate of capacitor `C_(1)`.
(ii) Electrostatic potential energy stored in capacitor `C_(3)`.

Text Solution

Verified by Experts

In the given figure, `C_(1)` and `C_(2)` are connected in series.
`(1)/(C.)=(1)/(6)+(1)/(12)`
`(1)/(C.)=(2+1)/(12)=(3)/(12)=(1)/(4)`
`C.=4muF`
Since, the capacitors are connected in series. so, same charge flows through each capacitor.
`:.q=C.V`
`q=4xx10^(-6)xx100`
`=400xx10^(-6)`
`=400muC`
(ii) `U_(E)=(1)/(2)CV^(2)`
`=(1)/(2)xx20xx10^(-6)xx(100)^(2)`
`=1xx10^(-1)=0.1J`
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