An alternating emf of 110 V is applied to a circuit containing a resistance R of `80 Omega` and an inductor L in series. The current is found to lag behind the supply voltage by an angle `theta=tan^(1) (3//4)`. Find the :
Inductive reactance

Explanation

To find the inductive reactance \( X_L \) in the given circuit, we can follow these steps:

### Step 1: Understand the relationship between the parameters
In an AC circuit with resistance \( R \) and inductance \( L \) in series, the current lags behind the voltage by an angle \( \theta \). The tangent of this angle is given by the ratio of the inductive reactance \( X_L \) to the resistance \( R \):
\[ \tan(\theta) = \frac{X_L}{R} \]

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