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An alternating emf of 110 V is applied t...

An alternating emf of 110 V is applied to a circuit containing a resistance R of `80 Omega` and an inductor L in series. The current is found to lag behind the supply voltage by an angle `theta=tan^(1) (3//4)`. Find the :
If the inductor has a coefficient of self inductance of 0.1 H, what is the frequency of the applied emf ?

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To solve the problem step by step, we need to find the frequency of the applied emf given the resistance, inductance, and the angle by which the current lags behind the voltage. ### Step 1: Identify the given values - Alternating emf (V) = 110 V - Resistance (R) = 80 Ω - Inductance (L) = 0.1 H - Angle (θ) = tan^(-1)(3/4) ...
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