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If the frequency of the incident radiati...

If the frequency of the incident radiation is increased from `4xx10^(15)Hz` to `8xx10^(15)Hz`. by how much will the stopping potential for a given photo-sensitive surface go up ?

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To solve the problem step by step, we will use the photoelectric effect principles and the relationship between frequency, stopping potential, and kinetic energy. ### Step 1: Identify the given frequencies We have two frequencies: - \( \nu_1 = 4 \times 10^{15} \, \text{Hz} \) - \( \nu_2 = 8 \times 10^{15} \, \text{Hz} \) ### Step 2: Write the formula for kinetic energy ...
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